The specific heat capacity is used in calculations where a given substance is heated from one temperature to another. The input heat results in a higher temperature of the substance. As long as the substance doesn't change its physical phase this works. All bets are off on this premise when there is a phase change.

There are 3 normal phases of matter that we are concerned with - solid, liquid, and gas. Each phase can directly change into the others and vice versa, therefore there are a total of 6 possible changes. Really this is 3 changes with 2 directions of change possible in each. The illustration below show this.

Note that each change has an associated name and that half of them are endothermic (the red arrows) and the other half are exothermic (the blue arrows). Each change occurs at a specific temperature as well. Let's look at each change and get the lingo down as well as the sign convention.

The temperature at the liquid/gas transition is the boiling point (bp) or the condensation point (rarely referred to BTW). Remember, it is the same temperature either way. For water, the boiling point is 100 °C (212 °F). The amount of heat to cause this change is the heat of vaporization or Δ*H*_{vap} and it is a positive quantity (endothermic). Water has a heat of vaporization of 2260 J/g. The heat of condensation is just the negative (exothermic) of that value. Also important here... notice how much bigger (almost 7×) the heat of vaporization is compared to the heat of fusion. This is because you must overcome ALL the IMFs of the substance to transition to gas phase.

The temperature of the transition is the sublimation point (solid to gas). The heat required for the transition is the heat/enthalpy of sublimation, Δ*H*_{sub}. The value (under standard conditions) of the heat of sublimation of a substance is equal to the sum of the heats of fusion and vaporization (Δ*H*_{sub} = Δ*H*_{fus} + Δ*H*_{vap} ).

There is no Δ*T* in the Calculation

ALL these transitions occur at the transition temperature and there is no change in temperature throughout the transition. So the calculation of the heat required just needs the Δ*H* value and the amount of substance. The "amount" can be mass in grams or amount in moles. Be sure and check the units on your Δ*H* value to see which amount you need to use: grams or moles. Here is the equation using mass (*m*).

*q*_{trans} = *m*_{trans}·Δ*H*_{trans}

Where the "trans" is for which ever transition you are calculating for. For example, if I want to calculate the amount of heat that will melt 25 grams of ice at 0 °C into 25 grams of water at 0 °C, I'd do the following.

*q*_{fusion} = (25 g)(334 J/g)

*q*_{fusion} = 8350 J

And to reiterate, just like with heat capacities, you can also have heats of transitions in terms of moles instead of grams. So always double check the units that your are given - you might have to convert from moles to grams or vice versa.

There is a TABLE of Phase Change Data in the Appendix

There is a table of phase change data (melting point, heat of fusion, boiling point, heat of vaporization) in the Appendix (Section 10.09). There are numberous substances listed. Look there for data for homework problems.